On Diophantine Equations \(2^x + 3y^2 = 4^z\) and \( 2^x + 7y^2 = 4^z\)

 
 
 
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    In this note, we study the Diophantine equations \(2^x + 3y^2 = 4^z\) and \(2^x+7y^2 = 4^z\). Also, we give solutions to \(2^x+dy^2 = 4^z\) for \(d = (2^k-1)/9, k\) a natural number = 0 (mod 6).

 

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Article ID: 708
 
DOI: 10.14419/ijams.v1i1.708




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